(5x)(-3x^-2)=15x

Solution for (5x)(-3x^-2)=15x equation:

(5x)(-3x^-2)=15x

We move all terms to the left:

(5x)(-3x^-2)-(15x)=0

We add all the numbers together, and all the variables

-15x+5x(-3x^-2)=0

We multiply parentheses

-15x^2-15x-10x=0

We add all the numbers together, and all the variables

-15x^2-25x=0

a = -15; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·(-15)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*-15}=\frac{0}{-30}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*-15}=\frac{50}{-30}
=-1+2/3
$